x^2-1,6=0

Solution for x^2-1,6=0 equation:

x^2-1.6=0

a = 1; b = 0; c = -1.6;
Δ = b2-4ac
Δ = 02-4·1·(-1.6)
Δ = 6.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6.4}}{2*1}=\frac{0-\sqrt{6.4}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6.4}}{2*1}=\frac{0+\sqrt{6.4}}{2}
=\frac{\sqrt{}}{2}
$